• Re: Olcott finally proves his point

    From olcott@polcott333@gmail.com to comp.theory,sci.logic,comp.ai.philosophy on Mon Jul 28 18:49:03 2025
    From Newsgroup: comp.ai.philosophy

    On 7/28/2025 6:37 PM, Richard Damon wrote:
    On 7/28/25 9:42 AM, olcott wrote:
    On 7/28/2025 4:22 AM, Fred. Zwarts wrote:
    Op 26.jul.2025 om 21:07 schreef olcott:
    On 7/26/2025 1:42 PM, joes wrote:
    Am Sat, 26 Jul 2025 08:18:55 -0500 schrieb olcott:
    On 7/26/2025 4:10 AM, Fred. Zwarts wrote:
    Op 26.jul.2025 om 01:36 schreef olcott:
    On 10/14/2022 7:44 PM, Ben Bacarisse wrote:

    I don't think that is the shell game.  PO really /has/ an H (it's >>>>>>>>> trivial to do for this one case) that correctly determines that >>>>>>>>> P(P)
    *would* never stop running *unless* aborted.  He knows and accepts >>>>>>>>> that P(P) actually does stop.  The wrong answer is justified by >>>>>>>>> what
    would happen if H (and hence a different P) where not what they >>>>>>>>> actually are.

    Ben wasn't agreeing with you here.


    counter-factual.
    Ben perfectly agreed with exactly half of what I said.
    Ben agreed that the Sipser approved criteria was met.

    <MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
         If simulating halt decider H correctly simulates its
         input D until H correctly determines that its simulated D
         would never stop running unless aborted then

         H can abort its simulation of D and correctly report that D
         specifies a non-halting sequence of configurations.
    </MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022> >>>>



    It does not matter whether he agreed or not, because it is a vacuous
    statement. H does not do a correct simulation. H does not correctly
    determines never stop running.
    When the conditions are not met, the conclusion is irrelevant and the
    whole statement is vacuous.

    *A more conventional way of saying that is*

    If simulating halt decider H correctly simulates its
    input D until H correctly determines that its simulated D
    *cannot possibly reach its own simulated final state*



    Which has to mean the correct simulation of it input, not ITS simulation
    of the input.


    Its simulation of its input is
    *The actual behavior that this INPUT actually specifies*

    Saying that decider H is required report on the behavior
    of machine M is a category error.

    Turing machines cannot directly report on the behavior
    of other Turing machines they can at best indirectly
    report on the behavior of Turing machines through the
    proxy of finite string machine descriptions such as ⟨M⟩.

    Thus the behavior specified by the input finite string
    overrules and supersedes the behavior of the direct
    execution.

    When machine description ⟨M⟩ correctly simulated
    by H cannot possibly reach its own simulated final
    halt state this proves that the ⟨M⟩ input to H specifies
    a non-terminating sequence of configurations.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
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  • From Richard Damon@Richard@Damon-Family.org to comp.theory,sci.logic,comp.ai.philosophy on Mon Jul 28 21:43:26 2025
    From Newsgroup: comp.ai.philosophy

    On 7/28/25 7:49 PM, olcott wrote:
    On 7/28/2025 6:37 PM, Richard Damon wrote:
    On 7/28/25 9:42 AM, olcott wrote:
    On 7/28/2025 4:22 AM, Fred. Zwarts wrote:
    Op 26.jul.2025 om 21:07 schreef olcott:
    On 7/26/2025 1:42 PM, joes wrote:
    Am Sat, 26 Jul 2025 08:18:55 -0500 schrieb olcott:
    On 7/26/2025 4:10 AM, Fred. Zwarts wrote:
    Op 26.jul.2025 om 01:36 schreef olcott:
    On 10/14/2022 7:44 PM, Ben Bacarisse wrote:

    I don't think that is the shell game.  PO really /has/ an H (it's >>>>>>>>>> trivial to do for this one case) that correctly determines >>>>>>>>>> that P(P)
    *would* never stop running *unless* aborted.  He knows and >>>>>>>>>> accepts
    that P(P) actually does stop.  The wrong answer is justified >>>>>>>>>> by what
    would happen if H (and hence a different P) where not what they >>>>>>>>>> actually are.

    Ben wasn't agreeing with you here.


    counter-factual.
    Ben perfectly agreed with exactly half of what I said.
    Ben agreed that the Sipser approved criteria was met.

    <MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022> >>>>>      If simulating halt decider H correctly simulates its
         input D until H correctly determines that its simulated D
         would never stop running unless aborted then

         H can abort its simulation of D and correctly report that D >>>>>      specifies a non-halting sequence of configurations.
    </MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022> >>>>>



    It does not matter whether he agreed or not, because it is a vacuous
    statement. H does not do a correct simulation. H does not correctly
    determines never stop running.
    When the conditions are not met, the conclusion is irrelevant and
    the whole statement is vacuous.

    *A more conventional way of saying that is*

    If simulating halt decider H correctly simulates its
    input D until H correctly determines that its simulated D
    *cannot possibly reach its own simulated final state*



    Which has to mean the correct simulation of it input, not ITS
    simulation of the input.


    Its simulation of its input is
    *The actual behavior that this INPUT actually specifies*

    Nope, by that logic, the input could mean anything.


    Saying that decider H is required report on the behavior
    of machine M is a category error.

    Nope, it is the definition.

    What "Category" are you saying it violates?

    The Problem SAYS it must decide on the behavior of the directly executed machine, which is represented/described by the input.

    If the input doesn't properly describe that program, *YOU* made the error.

    Sorry, you are just proving you LIE.


    Turing machines cannot directly report on the behavior
    of other Turing machines they can at best indirectly
    report on the behavior of Turing machines through the
    proxy of finite string machine descriptions such as ⟨M⟩.

    And it WAS given the proper description of the machine to decide on.

    Or, you just LIED that you D/DD/DDD are built by the proof.


    Thus the behavior specified by the input finite string
    overrules and supersedes the behavior of the direct
    execution.

    Nope. Just shows that you don't know what you are talking about.


    When machine description ⟨M⟩ correctly simulated
    by H cannot possibly reach its own simulated final
    halt state this proves that the ⟨M⟩ input to H specifies
    a non-terminating sequence of configurations.



    But since H doesn't correctly simulate its input, because it aborts it,
    you can't use a non-existent case.

    It seems you think lying is valid logic,
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  • From olcott@polcott333@gmail.com to comp.theory,comp.ai.philosophy,sci.logic on Sun Aug 3 08:44:09 2025
    From Newsgroup: comp.ai.philosophy

    On 8/3/2025 2:30 AM, Mikko wrote:
    On 2025-08-02 13:33:04 +0000, olcott said:

    On 8/2/2025 2:43 AM, Mikko wrote:

    When you make a claim about "DDD simulated by HHH" you apparently
    don't know what the words mean. The DDD simulated by HHH is the
    same as DDD executed directly and it specifies the same behaviour
    no matter how you call it.

    Counter factual

    Appearances can be false or misleading. However, in absense of contrary information, being true is more likely.

    There is no likely or unlikely to Boolean expressions.
    there is only true or false.

    _DDD()
    [00002192] 55 push ebp
    [00002193] 8bec mov ebp,esp
    [00002195] 6892210000 push 00002192 // push DDD
    [0000219a] e833f4ffff call 000015d2 // call HHH
    [0000219f] 83c404 add esp,+04
    [000021a2] 5d pop ebp
    [000021a3] c3 ret
    Size in bytes:(0018) [000021a3]

    When DDD is correctly emulated by HHH the definition
    of the x86 language specifies that the correctly
    emulated DDD cannot possibly ever reach past its own
    machine address of [0000219a].

    You can either comprehend this or fail to comprehend
    this. Disagreement is inherently incorrect.
    --
    Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
    hits a target no one else can see." Arthur Schopenhauer
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  • From Richard Damon@Richard@Damon-Family.org to comp.theory,comp.ai.philosophy,sci.logic on Sun Aug 3 15:22:36 2025
    From Newsgroup: comp.ai.philosophy

    On 8/3/25 9:44 AM, olcott wrote:
    On 8/3/2025 2:30 AM, Mikko wrote:
    On 2025-08-02 13:33:04 +0000, olcott said:

    On 8/2/2025 2:43 AM, Mikko wrote:

    When you make a claim about "DDD simulated by HHH" you apparently
    don't know what the words mean. The DDD simulated by HHH is the
    same as DDD executed directly and it specifies the same behaviour
    no matter how you call it.

    Counter factual

    Appearances can be false or misleading. However, in absense of contrary
    information, being true is more likely.

    There is no likely or unlikely to Boolean expressions.
    there is only true or false.

    _DDD()
    [00002192] 55         push ebp
    [00002193] 8bec       mov ebp,esp
    [00002195] 6892210000 push 00002192  // push DDD
    [0000219a] e833f4ffff call 000015d2  // call HHH
    [0000219f] 83c404     add esp,+04
    [000021a2] 5d         pop ebp
    [000021a3] c3         ret
    Size in bytes:(0018) [000021a3]

    When DDD is correctly emulated by HHH the definition
    of the x86 language specifies that the correctly
    emulated DDD cannot possibly ever reach past its own
    machine address of [0000219a].

    Which isn't a true statement for your HHH, as it doesn;t correctly
    emulate its DDD.



    You can either comprehend this or fail to comprehend
    this. Disagreement is inherently incorrect.


    Since it is a lie, what is to comprehend?

    Your problem is you try to decive people with wrong defintions.
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