From Newsgroup: comp.lang.c

<Input to LLM systems>
Simulating Termination Analyzer HHH correctly simulates its input until:
(a) Detects a non-terminating behavior pattern: abort simulation and
return 0.
(b) Simulated input reaches its simulated "return" statement: return 1.

typedef int (*ptr)();
int HHH(ptr P);

int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}

What value should HHH(DD) correctly return?
<Input to LLM systems>

They figured out the
*recursive simulation non-halting behavior pattern*
entirely on their own without prompting and figured
out that HHH(DD)==0 is correct also without prompting.

https://claude.ai/share/da9e56ba-f4e9-45ee-9f2c-dc5ffe10f00c

https://chatgpt.com/share/68939ee5-e2f8-8011-837d-438fe8e98b9c

https://grok.com/share/c2hhcmQtMg%3D%3D_810120bb-5ab5-4bf8-af21-eedd0f09e141
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

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From Newsgroup: comp.lang.c

On 8/12/2025 4:10 AM, Chris M. Thomasson wrote:

On 8/11/2025 3:17 PM, olcott wrote:>>

The basis of my work is summed up quite well by
Google [x86utm operating system].

I created the x86utm operating system so that any C
function can emulate any other C function in
debug_step mode.

HHH creates a new process context and emulates DD.
When DD calls HHH(DD) then the original HHH emulates
this new instance of itself that creates another
process context to emulate its instance of DD. Then
this DD calls yet another instance of HHH(DD). The
only limit to recursive depth is memory.

Claims to have solved the halting problem usually stem from one of a few common misunderstandings:

I am not making that claim.
I have shown that none of the conventional proofs actually
derive undecidability because their counter-example input
is decidable as non-halting.

Solving for a specific subset: They might create a program that can correctly predict the halting behavior of a limited class of programs, perhaps those without loops or those with a clear, finite upper bound on their recursion. They then mistakenly assume this partial solution
applies to all possible programs.

typedef int (*ptr)();
int HHH(ptr P);

int DD()
{
int Halt_Status = HHH(DD);
if (Halt_Status)
HERE: goto HERE;
return Halt_Status;
}

int main()
{
HHH(DD);
}

The above case is enough to refute all of the proofs.

Confusing a program with a Universal Turing Machine: They might write a program that can analyze the code of another program, but they don't
grasp the paradoxical machine that Alan Turing used to prove the problem
is unsolvable for all programs.

It turns out that no actual input can actually
do the opposite of what the Turing Machine halt
decider decides. When DD() is executed from main()
it is not an input to HHH().

Ignoring the theoretical model: The halting problem's proof applies to
the idealized model of a Turing Machine, which has infinite memory and infinite time. In the real world, every program will eventually halt due
to resource constraints (like stack overflow, as you mentioned), but
this doesn't solve the logical problem of predicting behavior for a theoretically infinite machine.

Machine M contains simulating halt decider H
M.q0 ⟨M⟩ ⊢* M.H ⟨M⟩ ⟨M⟩ ⊢* M.qy
M.q0 ⟨M⟩ ⊢* M.H ⟨M⟩ ⟨M⟩ ⊢* M.qn

*Repeats until aborted proving non-halting*
(a) M copies its input ⟨M⟩
(b) M invokes M.H ⟨M⟩ ⟨M⟩
(c) M.H simulates ⟨M⟩ ⟨M⟩

then M.H ⟨M⟩ ⟨M⟩ transitions to M.qn
causing M applied to ⟨M⟩ halt

The reason the Halting Problem is so widely accepted as unsolvable is because the proof is a solid, mathematical argument that has withstood decades of scrutiny. It's not a matter of opinion or a technical hurdle
to be overcome; it's a fundamental truth about the limits of computation.

Until you try rather than dismiss out-of-hand
the notion of a simulating halt decider. No one
has ever done this before my 2016 innovation.

When DD is correctly simulated by HHH the
"do the opposite" code becomes unreachable.

Fully operational code right here
https://github.com/plolcott/x86utm https://github.com/plolcott/x86utm/blob/master/Halt7.c
--
Copyright 2025 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer
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